of charge e and mass m, are accelerated across the selected high voltage V; energy conservation yields eV = (1=2)mv2, or e=m = v2=(2V), where v is the resulting speed of the electrons in the beam. Since we are using this experiment to measure the ratio e=m, the variables e, m, and v are each unknown.. This chemistry and physics video tutorial provides a basic introduction into the cathode ray tube experiment. JJ Thompson used this experiment to conclude t.
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fields on the electron trajectory (for example, bring a cell phone near the glass bulb). Is it significant enough to affect the measurements? 5. Obtain the value of the charge-to-mass ration, e/m, using the value Be estimated above and relationships described in Equations 9 and 10. References D. J. Griο¬iths. Magnetostatics, chapter 5, pages.. Thomson determined the ratio of the charge of the electron to its mass, the quantity e/m. ΓΈ L v E Figure 2: An electron passes through a region in which there is an electric field E pointing up. The electron is deflected downward by a distance d. Suppose that an electron with charge”-e” and mass m is moving to the right, as shown in Figure 2. It
